60 clinical MCQs in Weekly Exam: Pathology. A 62-year-old woman with IPF has worsening dyspnea over 2 weeks without infection. HRCT no. Kenya, Africa an...
Q1. A 62-year-old woman with IPF has worsening dyspnea over 2 weeks without infection. HRCT now shows new bilateral ground-glass opacities superimposed on her existing fibrosis. Most likely complication?
Answer: Acute exacerbation of IPF
Explanation: New ground-glass opacities in a patient with IPF, especially with worsening dyspnea, are highly suggestive of an acute exacerbation, which is a common and serious complication.
Q2. Pulmonary function testing in a patient with IPF is most likely to show which pattern?
Answer: Restrictive pattern (low TLC, normal or low FEV1/FVC)
Explanation: Idiopathic pulmonary fibrosis (IPF) is characterized by interstitial lung disease leading to stiff lungs, resulting in a restrictive pattern on PFTs, defined by a reduced total lung capacity (TLC) and a normal or relatively preserved FEV1/FVC ratio.
Q3. Which immunohistochemical marker distinguishes malignant mesothelioma from metastatic adenocarcinoma to the pleura?
Answer: WT1
Explanation: WT1 (Wilms Tumor 1) is a sensitive and specific marker for mesothelioma. CK7 can be positive in both. CK20 and TTF-1 are typically more associated with adenocarcinomas, particularly from the lung or GI tract.
Q4. A 55-year-old man with heart failure has a right-sided pleural effusion. Thoracentesis shows fluid protein of 2.1 g/dL, serum protein 7.0 g/dL, fluid LDH 88 U/L, and serum LDH 300 U/L. Most likely type of effusion?
Answer: Transudate
Explanation: This effusion is a transudate. Using Light's criteria: Fluid protein/serum protein ratio (2.1/7.0 = 0.3) is <0.5. Fluid LDH/serum LDH ratio (88/300 = 0.29) is <0.6. These values are characteristic of a transudate, often due to systemic factors like heart failure.
Q5. A 48-year-old woman with breast cancer develops a right pleural effusion. Thoracentesis yields fluid protein of 5.2 g/dL, serum protein 6.8 g/dL, fluid LDH 420 U/L, and serum LDH 310 U/L. Cytology shows malignant cells. Most likely type of effusion?
Answer: Exudate
Explanation: This effusion is an exudate. Using Light's criteria: Fluid protein/serum protein ratio (5.2/6.8 = 0.76) is 0.5. Fluid LDH/serum LDH ratio (420/310 = 1.35) is 0.6. The presence of malignant cells further supports an exudate, specifically a malignant effusion.
Q6. A 35-year-old man undergoes thoracic duct injury during left-sided neck dissection surgery. Two days later he develops a left pleural effusion. Thoracentesis yields milky white fluid with triglycerides of 210 mg/dL. Most likely diagnosis?
Answer: Chylothorax
Explanation: Milky white pleural fluid with elevated triglycerides (typically 110 mg/dL) following thoracic duct injury is diagnostic of chylothorax, caused by leakage of lymphatic fluid.
Q7. A 45-year-old man has a 3-month history of recurrent sinusitis, epistaxis, haemoptysis, and haematuria. CXR shows bilateral cavitating nodules. Urinalysis shows red cell casts. c-ANCA (PR3-ANCA) is strongly positive. Most likely diagnosis?
Answer: Granulomatosis with polyangiitis (Wegener's)
Explanation: This constellation of symptoms (upper and lower respiratory tract involvement, renal disease, positive c-ANCA/PR3-ANCA) is classic for Granulomatosis with Polyangiitis (Wegener's).
Q8. A 38-year-old woman with asthma develops peripheral blood eosinophilia of 18%, p-ANCA positivity, and a new mononeuritis multiplex. CXR shows transient pulmonary infiltrates. Most likely diagnosis?
Answer: Eosinophilic granulomatosis with polyangiitis (Churg-Strauss)
Explanation: The presence of asthma, eosinophilia, p-ANCA positivity, mononeuritis multiplex, and transient pulmonary infiltrates is highly suggestive of Eosinophilic Granulomatosis with Polyangiitis (formerly Churg-Strauss syndrome).
Q9. A 24-year-old male smoker presents with haemoptysis and progressive dyspnea. Urinalysis shows proteinuria and red cell casts. CXR reveals bilateral alveolar infiltrates. Anti-GBM antibodies are strongly positive. Renal biopsy shows linear IgG deposits along the glomerular basement membrane. Most likely diagnosis?
Answer: Goodpasture syndrome
Explanation: The combination of pulmonary hemorrhage (hemoptysis), glomerulonephritis (proteinuria, red cell casts), positive anti-GBM antibodies, and linear IgG deposition on biopsy is diagnostic of Goodpasture syndrome.
Q10. A 55-year-old granite quarry worker has 20 years of exposure to silica dust. He now has progressive dyspnea and a dry cough. CXR shows upper lobe predominant nodules with eggshell calcification of hilar lymph nodes. Pulmonary function shows a restrictive pattern. Most likely diagnosis?
Answer: Silicosis
Explanation: The occupational history of silica exposure, upper lobe predominant nodules, eggshell calcification of hilar lymph nodes, and restrictive PFTs are characteristic findings of silicosis.
Q11. A 32-year-old woman with no cardiopulmonary disease has progressive exertional dyspnea, syncope on exertion, and loud P2 on auscultation. Right heart catheterization shows mean pulmonary artery pressure of 38 mmHg with normal pulmonary capillary wedge pressure. Most likely diagnosis?
Answer: Pulmonary arterial hypertension (PAH)
Explanation: Elevated mean pulmonary artery pressure with a normal pulmonary capillary wedge pressure is diagnostic of pulmonary arterial hypertension (PAH), often presenting with exertional dyspnea and syncope.
Q12. A 70-year-old man with severe COPD has increasing drowsiness. ABG shows pH 7.28, PaO2 55 mmHg, PaCO2 72 mmHg, and HCO3 32 mEq/L. Most likely type of respiratory failure?
Answer: Type 2 (hypercapnic)
Explanation: The ABG demonstrates significant hypoxemia (PaO2 55 mmHg) and hypercapnia (PaCO2 72 mmHg) with a resultant respiratory acidosis (pH 7.28). This combination, especially with the elevated PaCO2 and decreased pH, indicates Type 2 (hypercapnic) respiratory failure, common in severe COPD exacerbations.
Q13. A 63-year-old woman has sudden 'knife-like' chest pain radiating to the back, poorly controlled hypertension, and a widened mediastinum on CXR. CK is normal. Most likely diagnosis?
Answer: Aortic dissection
Explanation: Sudden onset severe chest pain radiating to the back, history of hypertension, and widened mediastinum on CXR are classic signs of aortic dissection. Normal CK rules out myocardial infarction. Esophageal rupture typically presents with more vomiting or retroperitoneal air.
Q14. A man is examined 4 days after a large transmural anterolateral MI with cardiogenic shock. Most likely microscopic finding?
Answer: Coagulative necrosis with early neutrophil infiltration
Explanation: At 4 days post-MI, the hallmark microscopic findings are coagulative necrosis of the cardiomyocytes and the initial inflammatory response, characterized by neutrophil infiltration. Myocytolysis starts around day 1, fibrosis begins later (around day 7-10), and scar formation is much later.
Q15. A 45-year-old woman has orthopnea, dysphagia, and a prior stroke. CXR shows near-normal LV but prominent left atrial border. Most likely condition?
Answer: Mitral stenosis
Explanation: Orthopnea and a prominent left atrial border on CXR are suggestive of left atrial enlargement. Dysphagia can be caused by an enlarged left atrium compressing the esophagus. Mitral stenosis is the most common cause of significant left atrial enlargement and often leads to these symptoms. A prior stroke is a risk factor for atrial fibrillation, which can be associated with mitral valve disease.
Q16. A 16-year-old is stabbed in the left chest. BP barely obtainable, lungs clear, heart sounds barely audible. Most useful treatment?
Answer: Tube thoracostomy
Explanation: The presentation of hypotension, clear lungs, and muffled heart sounds after chest trauma suggests a tension pneumothorax or hemothorax. Tube thoracostomy is the definitive treatment to evacuate air or blood from the pleural space and re-expand the lung.
Q17. A 19-year-old with mid-systolic click, mitral insufficiency, aortic root dilation, and a dislocated lens dies suddenly. Ruptured chordae found at autopsy. Most likely gene mutation?
Answer: FBN1
Explanation: This patient has features suggestive of Marfan syndrome (tall stature, aortic root dilation, dislocated lens, mitral valve prolapse with ruptured chordae). The gene responsible for Marfan syndrome is FBN1, which encodes fibrillin-1.
Q18. A 72-year-old woman with no prior illness has three syncopal episodes then pulmonary edema. CXR shows LV prominence only. Cholesterol normal. Most likely diagnosis?
Answer: Severe aortic stenosis
Explanation: Syncope is a classic symptom of severe aortic stenosis due to inadequate blood flow to the brain during exertion. The subsequent development of pulmonary edema, LV prominence on CXR, and the patient's age make severe aortic stenosis highly likely.
Q19. A 17-year-old short girl with absent puberty, webbed neck, upper extremity hypertension, diminished lower extremity pulses, and rib notching on CXR. Most likely cardiovascular abnormality?
Answer: Coarctation of the aorta
Explanation: The combination of short stature, webbed neck, absent puberty (suggestive of Turner syndrome), and hypertension with diminished lower extremity pulses and rib notching (due to collateral circulation) strongly points to coarctation of the aorta. While Turner syndrome can have cardiovascular issues, coarctation is the primary cause of these specific findings.
Q20. A 65-year-old man with 20 years of uncontrolled diabetes has sudden severe abdominal pain, diminished lower-extremity pulses, and a pulsatile abdominal mass. CK normal. Most likely condition?
Answer: Abdominal aortic aneurysm rupture
Explanation: A pulsatile abdominal mass, severe abdominal pain, and diminished lower extremity pulses in an elderly patient with long-standing diabetes (a risk factor for atherosclerosis) are highly suggestive of a ruptured abdominal aortic aneurysm. The rupture can cause referred pain and affect distal pulses.
Q21. A 49-year-old woman with poorly controlled atrial fibrillation dies after a stroke. Autopsy shows fused mitral leaflets, shortened chordae, and thrombus-filled enlarged left atrium. Most likely underlying cause?
Answer: Rheumatic heart disease
Explanation: Fused mitral leaflets, shortened chordae, left atrial enlargement, and atrial fibrillation are classic findings of chronic rheumatic heart disease. It is a common cause of mitral valve disease and predisposes to atrial fibrillation and embolic strokes.
Q22. A 23-year-old woman with a malar rash has a friction rub, a faint systolic murmur, small mitral vegetations on echo, and a very high anti-Smith antibody titer. Most likely diagnosis?
Answer: Systemic lupus erythematosus (SLE) with Libman-Sacks endocarditis
Explanation: The combination of malar rash, friction rub (pericarditis), murmur (endocarditis), small vegetations (consistent with non-bacterial thrombotic endocarditis/Libman-Sacks), and high anti-Smith antibodies is characteristic of Systemic Lupus Erythematosus (SLE), particularly with cardiac involvement (Libman-Sacks endocarditis).
Q23. A fetus at 18 weeks has a VSD, overriding aorta, and marked pulmonic atresia. If liveborn, what physical finding would most likely result?
Answer: Cyanosis
Explanation: This describes a severe complex congenital heart defect, often referred to as a form of truncus arteriosus or a severe form of Tetralogy of Fallot with atresia. The lack of a functional pulmonary outflow tract and the mixing of oxygenated and deoxygenated blood would lead to significant cyanosis (bluish discoloration).
Q24. A 50-year-old man has 3 hours of substernal chest pain, ST elevation in V1–V6, and pulmonary edema. Which lab finding is most likely?
Answer: All of the above
Explanation: Given the clinical presentation of acute myocardial infarction (chest pain, ECG changes) with complications (pulmonary edema), all three cardiac biomarkers (Troponin I, CK-MB, and myoglobin) would likely be elevated. Troponin is the most specific and sensitive marker for myocardial injury.
Q25. A 52-year-old woman undergoes thyroidectomy for a well-circumscribed, encapsulated thyroid nodule. History shows uniform follicles resembling normal thyroid architecture. Which of the following is the most accurate designation?
Answer: Follicular adenoma
Explanation: A well-circumscribed, encapsulated nodule with uniform follicles resembling normal thyroid architecture is the histological description of a benign follicular adenoma. Malignant tumors like papillary or anaplastic carcinoma have different architectural features and lack encapsulation.
Q26. A 65-year-old man is a firm mass in the sigmoid colon. Colonoscopy shows an ulcerated lesion with irregular borders. Biopsy demonstrates invasion through the muscularis propria. Which histological feature most strongly distinguishes this lesion as malignant rather than benign?
Answer: Nuclear atypia
Explanation: Nuclear atypia (variation in nuclear size, shape, and chromatin) is a hallmark of malignancy and is crucial for distinguishing benign from malignant lesions, even when other features like invasion are present. While increased mitoses and glandular formation can be seen in both, atypia is a more definitive indicator of malignancy.
Q27. A 45-year-old woman has chronic myeloid leukemia (CML). Cytogenetic analysis reveals a reciprocal translocation between chromosomes 9 and 22. The resultant fusion gene codes for a protein with which abnormal activity?
Answer: Constitutive tyrosine kinase activity
Explanation: The t(9;22) translocation creates the Philadelphia chromosome, leading to the formation of the BCR-ABL fusion gene. This gene product is a constitutively active tyrosine kinase that drives the uncontrolled proliferation of myeloid cells in CML.
Q28. A 33-year-old woman with breast cancer is found to have HER2/neu gene amplification. Which of the following best describes the mechanism by which HER2/neu promotes oncogenesis?
Answer: Activation of growth factor signaling pathways
Explanation: HER2/neu (ERBB2) is a receptor tyrosine kinase. Amplification of its gene leads to overexpression of the HER2 protein, which then signals aberrantly through downstream pathways (e.g., PI3K/Akt, MAPK) promoting cell proliferation, survival, and invasion, thereby driving oncogenesis.
Q29. A 28-year-old man presents with bilateral retinoblastomas. Genetic analysis reveals a germline mutation in one allele of the RB gene, followed by somatic loss of the second allele. This exemplifies which principle?
Answer: Two-hit hypothesis of tumorigenesis
Explanation: The development of bilateral retinoblastoma in an individual with a germline mutation in one RB allele, followed by a somatic mutation in the other allele, is a classic example of the 'two-hit hypothesis' (Knudson's hypothesis) for tumor suppressor genes. Both alleles must be inactivated for the tumor to develop.
Q30. A 62-year-old man with chronic hepatitis B develops hepatocellular carcinoma. Molecular studies reveal inactivation of p53. Which of the following best describes the normal role of p53 in preventing tumor development?
Answer: Induces cell cycle arrest and apoptosis in response to DNA damage
Explanation: p53 is a critical tumor suppressor gene. Its normal function is to sense DNA damage and trigger appropriate cellular responses, such as cell cycle arrest to allow for repair or induction of apoptosis if the damage is irreparable. Inactivation of p53 removes this crucial protective mechanism, allowing damaged cells to proliferate and accumulate further mutations.
Q31. A point mutation in the RAS gene that locks it in an active GTP-bound state results in which cellular effect?
Answer: Uncontrolled cell proliferation
Explanation: RAS proteins are molecular switches involved in signal transduction pathways that regulate cell growth and proliferation. When mutated to be constitutively active (locked in the GTP-bound state), they continuously signal for cell division, leading to uncontrolled proliferation, a hallmark of cancer.
Q32. The ERBB2 (HER2/neu) oncogene contributes to tumorigenesis primarily by:
Answer: Activating downstream signaling pathways that promote cell growth and survival
Explanation: ERBB2 (HER2/neu) is a receptor tyrosine kinase. Its overexpression due to gene amplification leads to constitutive activation of downstream signaling pathways like PI3K/Akt and MAPK, which promote cell proliferation, survival, and inhibit apoptosis, thus contributing to tumor development and progression.
Q33. Autocrine stimulation of growth factor receptors is best exemplified by:
Answer: A tumor cell producing a growth factor that binds to receptors on its own surface
Explanation: Autocrine signaling occurs when a cell produces a signaling molecule (like a growth factor) that binds to receptors on its own surface, thereby stimulating itself. This is a common mechanism in cancer cells to promote their own growth and survival.
Q34. Mutation of the RB1 gene promotes cancer development by:
Answer: Releasing the E2F transcription factor, leading to uncontrolled cell cycle progression
Explanation: The RB1 gene encodes the retinoblastoma protein (pRB), a key regulator of the cell cycle. Under normal conditions, pRB binds to and inhibits the E2F transcription factor, preventing entry into the S phase. Mutation or inactivation of RB1 releases E2F, leading to uncontrolled progression through the cell cycle and promoting tumor development.
Q35. Loss of function of the TGF-β signaling pathway contributes to tumorigenesis by:
Answer: Removing a key inhibitor of cell proliferation
Explanation: Transforming Growth Factor-beta (TGF-β) typically acts as a suppressor of cell proliferation in normal epithelial cells. Loss of function mutations in components of the TGF-β signaling pathway removes this inhibitory signal, allowing for uncontrolled cell growth and contributing to tumorigenesis.
Q36. The anti-apoptotic effect of BCL-2 overexpression in follicular lymphoma occurs due to:
Answer: Inhibition of the intrinsic pathway of apoptosis
Explanation: BCL-2 is a proto-oncogene that acts as an inhibitor of apoptosis. Overexpression of BCL-2, as seen in follicular lymphoma (often due to t(14;18) translocation), blocks the intrinsic pathway of apoptosis by preventing the release of cytochrome c from mitochondria, thereby promoting cell survival.
Q37. The genetic defect associated with Fabry's disease is most likely carried on
Answer: The X chromosome
Explanation: Fabry disease is an X-linked lysosomal storage disorder caused by mutations in the GLA gene, which is located on the X chromosome. This explains its X-linked inheritance pattern.
Q38. Amount of dietary iodine in the control of thyroid hormone secretion
Answer: Is essential for the synthesis of thyroid hormones
Explanation: Dietary iodine is a critical component for the synthesis of thyroid hormones (thyroxine and triiodothyronine) by the thyroid gland. Without sufficient iodine, thyroid hormone production is impaired.
Q39. Movement of Cl- ion from gastric cells into the gastric cavity
Answer: Is mediated by the H+/K+-ATPase pump
Explanation: The H+/K+-ATPase pump in gastric parietal cells secretes H+ into the gastric lumen. The movement of Cl- into the gastric cavity is coupled to this process, often indirectly through counter-transport mechanisms that maintain electrochemical balance, and is a key component of gastric acid secretion.
Q40. Myeloid cells in innate and adaptive immunity EXCLUDE the following:
Answer: T lymphocytes
Explanation: T lymphocytes are lymphocytes, which are derived from the common lymphoid progenitor, and are central to adaptive immunity. Myeloid cells (neutrophils, macrophages, dendritic cells) are derived from the common myeloid progenitor and are key components of innate immunity, and dendritic cells also play a crucial role in bridging innate and adaptive immunity.
Q41. The following statement is FALSE about the cells arising from the common lymphoid progenitor
Answer: They are phagocytic cells that engulf pathogens
Explanation: Phagocytic cells like macrophages and neutrophils arise from the common myeloid progenitor, not the common lymphoid progenitor. Cells from the common lymphoid progenitor (B cells, T cells, NK cells) are primarily involved in adaptive and certain aspects of innate immunity (NK cells), and include antibody production and cell-mediated immunity.
Q42. While complete aerobic oxidation of one mole of glucose in the cell yields 38 moles of ATP, complete catabolism of one mole of a 6- carbon atoms fatty acid through the citric acid cycle yields
Answer: Significantly more ATP than glucose
Explanation: Fatty acids are highly energy-dense molecules. The complete catabolism of a 6-carbon fatty acid (like palmitate, though that's 16 carbons) through beta-oxidation and the citric acid cycle yields considerably more ATP than the complete oxidation of one mole of glucose. For example, a 16-carbon fatty acid yields over 100 ATP molecules.
Q43. Immune privileged sites include the following EXCEPT:
Answer: Liver
Explanation: The liver is not typically considered an immune privileged site in the same way as the brain, eyes, or testes. While it has unique immunological properties, it is a site of significant immune activity and interaction, and is susceptible to immune-mediated damage (e.g., in hepatitis).
Q44. The human genome
Answer: Consists of approximately 20,000-25,000 protein-coding genes
Explanation: The human genome contains an estimated 20,000-25,000 protein-coding genes. It also contains a large amount of non-coding DNA. Genes are arranged on multiple chromosomes, not a single one.
Q45. The following are characteristics of skeletal muscle fibres EXCEPT:
Answer: Involuntary control
Explanation: Skeletal muscle fibers are characterized by their striated appearance due to the organized arrangement of actin and myosin, are multinucleated (syncytia formed by fusion of myoblasts), and possess contractile proteins. However, skeletal muscle is under voluntary control, not involuntary.
Q46. Increasing the frequency of stimulation so that a muscle contracts without relaxation is called
Answer: Tetanus
Explanation: Tetanus (or tetanic contraction) occurs when the frequency of stimulation of a muscle fiber is so high that individual muscle twitches fuse together, resulting in a sustained, smooth contraction with no relaxation between stimuli.
Q47. Which type of sensation is most affected if the lesion is in the sensory cortex?
Answer: Touch and proprioception
Explanation: The primary somatosensory cortex (postcentral gyrus) is responsible for processing sensations of touch, pressure, vibration, proprioception (body position), and kinesthesia (body movement). Lesions here would most significantly affect these modalities.
Q48. There are several important differences between a chemical and an electrical synapse. Which of the following statements does NOT constitute a a difference between these two types of synapses?
Answer: Neurotransmitters are released from the presynaptic terminal in both types of synapses.
Explanation: Neurotransmitter release from the presynaptic terminal is a characteristic feature of chemical synapses, not electrical synapses. Electrical synapses transmit signals via direct ion flow through gap junctions.
Q49. glucosuria is usually present without ketonuria
Answer: In renal glucosuria
Explanation: Renal glucosuria is a condition where the renal tubules have a reduced capacity to reabsorb glucose, leading to glucose in the urine even when blood glucose levels are normal or only mildly elevated. This occurs without ketonuria, unlike in uncontrolled diabetes mellitus where both can be present.
Q50. maleinimide 2. monoiodine acetate 3. sodium fluoride 4. cresol
Answer: Inhibitor of glycolysis
Explanation: Maleinimide, monoiodine acetate, and sodium fluoride are all known inhibitors of glycolysis, acting at different steps of the pathway. Cresol is a phenol derivative and not a direct glycolytic inhibitor in this context.
Q51. glucose 2. sucrose 3. xylose 4. galactose
Answer: Monosaccharide
Explanation: Glucose, xylose, and galactose are monosaccharides. Sucrose is a disaccharide composed of glucose and fructose. Glucose and galactose are hexoses (6-carbon sugars), while xylose is a pentose (5-carbon sugar).
Q52. Decreased values in conjunction with pleural fluid/blood glucose ratios <1.0 may occur in effusions due to underlying bacterial, tuberculous, malignant, and rheumatic disease.
Answer: Pleural fluid glucose
Explanation: A low pleural fluid glucose level (and a low pleural fluid/serum glucose ratio <1.0) is characteristic of exudative effusions caused by increased glucose utilization by inflammatory cells (bacteria, malignant cells) or impaired glucose transport into the pleural space. This is commonly seen in bacterial pneumonia, empyema, tuberculous pleuritis, and malignant effusions.
Q53. 150mins 90mg/dL
Answer: Impaired glucose tolerance
Explanation: This refers to a 2-hour post-prandial glucose level. A level greater than 90 mg/dL but less than 200 mg/dL at 2 hours after a glucose load typically indicates impaired glucose tolerance (prediabetes).
Q54. The mean blood glucose of the preceding 6-8 weeks is correlated with corresponding glycohemoglobin value.
Answer: True
Explanation: Glycohemoglobin (HbA1c) reflects the average blood glucose levels over the preceding 6-8 weeks because glucose attaches to hemoglobin in red blood cells, and the lifespan of red blood cells is approximately that duration. Thus, HbA1c is a reliable indicator of long-term glycemic control.
Q55. The pancreas synthesizes insulin but unable to secrete.
Answer: Type 2 diabetes mellitus
Explanation: Type 2 diabetes mellitus is characterized by insulin resistance and a relative deficiency of insulin secretion. While the pancreas may still synthesize insulin, the ability to secrete adequate amounts in response to glucose levels is impaired.
Q56. plasma and serum may be stored for cholesterol assay for up to 4 days at 4C.
Answer: True
Explanation: For many lipid assays, including cholesterol, samples can be stored at 4°C for up to 4 days without significant degradation or alteration of results, making this statement true.
Q57. hemoglobin 2. ascorbic acid 3. heparin 4. bilirubin
Answer: Interferes with spectrophotometric assays
Explanation: Hemoglobin, ascorbic acid (Vitamin C), and bilirubin can all interfere with spectrophotometric measurements of various analytes due to their color. Heparin is an anticoagulant. Bilirubin is a breakdown product of red blood cells and imparts a yellow color.
Q58. patients with hyperthyroidism
Answer: All of the above
Explanation: Hyperthyroidism is characterized by excessive production of thyroid hormones (T3 and T4), leading to suppressed TSH levels. In autoimmune causes like Graves' disease, thyroid antibodies are often present.
Q59. LDL on electropheretic separation migrate in the a-globulin position
Answer: False
Explanation: On typical lipid electrophoresis, LDL (low-density lipoprotein) migrates in the beta-globulin position, not the alpha-globulin position. Alpha-globulins are primarily associated with HDL (high-density lipoprotein).
Q60. structural protein of chylomicron
Answer: Apolipoprotein B-48
Explanation: Apolipoprotein B-48 (ApoB-48) is the defining structural protein of chylomicrons, synthesized exclusively in the intestinal cells. Other apolipoproteins are acquired from HDL and are involved in various functions like lipid transfer and enzyme activation.